PLEASE HELP I WILL GIVE BRAINLIEST IF TWO PPL ANSWER!! :C Simplify (write without the absolute value sign):
|x - 120|, if x < -120
|x - ( -12 )|, if x > -12
|x - ( -12 )|, if x < -12
|x - ( - 12 )|, if x = -12
|x ÷3|, if x > 0
|x÷3|, if x < 0

x+120 , if x < -120

x+12 , if x > -12

x+12 , if x < -12

x+12 , if x = -12

x÷3 , if x > 0

x÷3 , if x < 0

Step-by-step explanation:

Well whatever is in the absolute value sign is always positive.

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Step-by-step explanation:

|x - 120|, if x < -120  . . .  the function changes behavior at x=120, at x < -120, the function value is -x+120

|x - ( -12 )|, if x > -12  . . .  in this domain, the function is unchanged: x + 12

|x - ( -12 )|, if x < -12  . . .  in this domain, the function is negated: -x -12

|x - ( - 12 )|, if x = -12  . . .  at this point, the function is 0

|x ÷3|, if x > 0  . . .  for positive x, the function is unchanged: x/3

|x÷3|, if x < 0  . . .  for negative x, the function is negated: -x/3

is this part of a question or something