The line 1 has equation 5x + 6y + 30 = 0. Given that P is the point (3, -1), find
(i) the coordinates of the point where l crosses the
x-axis,
(ii) the coordinates of the point of intersection
of l with the line x = 2,
(iii) the equation of the line passing through P
and having the same gradient as I,
(iv) the equation of the line passing through P
and having a gradient of 0.
w through the points ACO 3).

Step-by-step explanation:

i) the x-intercept is when y=0

5x+6(0)+30=0

5x=-30

x=-6

hence the point is (-6,0)

ii)5(2)+6y+30=0

10+6y+30=0

6y=-40

y=-20/3

hence the point of intersection is (2,-20/3)

iii) y+1=-5/6(x-3)

6y+6=-5x+15

6y+5x=9

iv) y+1=0(x-3)

y=-1

207/8 is the right

b. y = 4x - 2

step-by-step explanation:

to find a parallel equation to an equation, make sure both equations have the same slope but different y-intercepts.

y = 4x + 1

4 = slope

1 = y-intercept

y = 4x - 2

4 = slope

-2 = y-intercept

they both have the same slope but different y-intercepts, so, b. is the correct answer.

and to check your work, you can graph both equations. : )