A father is 28 years older than his daughter. In six years' time, he will be three times her age. Find their present ages. Please include your working out!!

Step-by-step explanation:

Let the age of daughter be x

Then the age of father will be x + 28

In 6 years time:-

The age of father = x + 28 + 2 = 30 + x

The age of daughter = x + 6

According to the question,

Father will be three times the age of his daughter.

30 + x = 3(x + 6)

30 + x = 3x + 18

x - 3x = 18 - 30

-2x = - 12

x = - 12/-2

x = 6

So therfore,

Daughter's present age = 6 years

Father's present age = 34 years

Hope this helps :)

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1