The perimeter of a triangle is34 ft. One side of the triangle is 2 times the second side. The third side is 6 ft longer than the second side. Find the length of each side

Let the second side = x

The first side is 2x ( 2 times the second side)

The third side is x + 6 ( 6 feet longer than the second side)

Now you have: x + 2x + x + 6 = 34

Simplify to get:

4x + 6 = 34

Subtract 6 from both sides

4x = 28

Divide both sides by 4:

X = 7

1st side = 2x = 2*7 = 14 feet

2nd side = x = 7 feet

3rd side = x + 6 = 7 + 6 = 13 feet

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.

i would say b) is your answer

sorry if im wrong

step-by-step explanation: