Consider again the tossing of a pair of dice. Find the probability the sum is greater than 6. (Round to the hundredths)

7/12 or 58.333%

Step-by-step explanation:

There are the 36 possible outcomes.  

6+5+4+3+2+1 = 21 are greater than 6  

Probability is 21/36 = 7/12 or 58.333%

see several wrong answers posted (and one correct answer so far), so I will try to present the correct solution.

Total number of possibilities is 36 (6 x 6), two six sided dice.

Of these possibilities, 21 are greater than 6, listed here: 6 ways to roll a 7, 5 ways to roll an 8, 4 ways to roll a 9, 3 ways to roll a 10, 2 ways to roll an 11, and 1 way to roll a 12.

These are the qualifying rolls: (1,6),(2,5),(2,6),(3,4),(3,5),(3,6),(4,3),(4,4),(4,5),(4,6),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6) - 21 total sums over 6

So the probability is 21/36, or simplifying, 7/12. Converted to a percentage, it is 58.333%.

what is the information provided?

step-by-step explanation: