A rocket is launched from a tower. The height of the rocket, y in feet, is rel time after launch, x in seconds, by the given equation. Using this equation
time that the rocket will hit the ground, to the nearest 100th of second.
y = -16x² + 147x + 80

9514 1404 393

  9.70 seconds

Step-by-step explanation:

The zero of the equation can be found using the quadratic formula.

  ax² +bx +c = 0

  x = (-b ±√(b² -4ac))/(2a)

We are only interested in the positive value of x, so this will be ...

  x = (-147 -√(147² -4(-16)(80)))/(2(-16)) = (147 +√2679)/32

  x ≈ 9.7028 ≈ 9.70 . . . . seconds

The rocket will hit the ground after about 9.70 seconds.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

can you rephrase the question ? it is unclear : -)

step-by-step explanation: