Given the function f (x) = x² + 8x + 7, what are the zeros of f?

x = - 7, x = - 1

Step-by-step explanation:

To find the zeros let f(x) = 0 , that is

x² + 8x + 7 = 0

Consider the factors of the constant term (+ 7) which sum to give the coefficient of the x- term (+ 8)

The factors are + 7 and + 1 , since

7 × 1 = + 7 and 7 + 1 = + 8 , then

x² + 8x + 7 = 0

(x + 7)(x + 1) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 7 = 0 ⇒ x = - 7

x + 1 = 0 ⇒ x = - 1

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

answer: i literally just answered this question but they want me to do it again

step-by-step explanation: