Find an equation of the line that passes through (6,-1) and has a slope of 3

The equation is: y y = 5/4 * x - 13

Step-by-step explanation:

The slope-intercept y = mx + c form of a straight line is In this case we have a point, (x, y) and the slope, m so all we need is a value for c. Substitute into y = mx + c - 3 = 5/4 * (8) + c - 3 = 10 + c c = - 13 y = 5/4 * x - 13 The equation is: y the formula for the situation have a point, (x 1 ,y 1 ) and the slope, Or you can use where you (m) y-y 1 =m(x-x 1 ) y - (- 3) = 5/4 * (x - 8) y + 3 = 5/4 * x - 10 y = 5/4 * x - 13 Answer link < II