How much did a case of JUICE cost? The math club and the science club had a fundraiser. The math club spent $135 buying 6 cases of juice and 1 case of bottled water. The science club spent $110 buying 4 cases of juice and 2 cases of bottled water.​

Let x=cost of a case of juice

And y=cost of a case of bottled water

Now we are told that:

6x+y=$135eq1cases and cost for the math club

4x+2y=$110eq2cases and cost for the science club

Multiply eq1 by 2 and we get:

12x+2y=$270eq1a

4x+2y=$110eq2

subtract eq2 from eq1a and we get:

8x=$160 divide both sides by 8

x=$20cost of a case of juice

substitute x=$20 into eq2 and we have:

4*$20+2y=$110 or

$80+2y=$110 subtract $80 from both sides

$80-$80+2y=$110-$80 collect like terms

2y=$30 divide both sides by 2

y=$15cost of a case of bottled water

CK

6*20+1*15=135

120+15=135

135=135

also

4*20+2*15=110

80+30=110

110=110

Step-by-step explanation:

Hope this helps.       :)

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step-by-step explanation:

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step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

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⇒ ⇒

factorizing, we get that:

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then, the solutions are: or

nothing extraneous has been found!