Does anyone know how to do this ? I need to show my work btw

m∠ECD = 145°

m∠FCA = 35°

m∠PDF = 70°

Step-by-step explanation:

For ∠ECD:

- You can find this angle using supplementary angles. ∠ECD and ∠ECB are supplementary, meaning they add to 180°. Since the measure of ∠ECB is provided, you can subtract that from 180° to get m∠ECD:

  180 - 35 = 145°, so m∠ECD = 145°

For ∠FCA:

- You can solve this problem using the Vertical Angles theorem. It states that vertical angles are congruent. ∠FCA's vertical angle pair is ∠ECB, which is 35°, so you can deduce that m∠FCA = 35°

For ∠PDF:

- You can find the measure of this angle by using supplementary angles like for ∠ECD. ∠PDC is supplementary to ∠PDF, and it's value is given. so you can find PDF by subtracting the value of ∠PDC from 180:

  180 - 110 = 70°; m∠PDF = 70°

an = 22 + (n-1) *6

110 seats

step-by-step explanation:

an=a1+(n-1)(d)

a1 = 22   this is the first item in the sequence

d =6   this is how the sequence goes up

a)   an = 22 + (n-1) *6

b) a12 = 22 + (12-1) *6

    a12 = 22+11*6

  a12 = 22 +88

  a12 = 110