Ken is going to throw a biased dice once. The probability that the dice will land on six is 0.3

(b) What is the probability that the dice will not land on six?

0.7

Step-by-step explanation:

Given a biased dice :

Probability of landing on 6 = P(6) ;

P(6) = 0.3

Recall :

P(A') = 1 - P(A)

Therefore,

If

P(6) = 0.3

P(not landing on 6) ; P(not 6) ;

P(not 6) = 1 - P(6)

P(not 6) = 1 - 0.3 = 0.7

Hence, Probability of not landing on 6 = 0.7

3/6   and 9/18

step-by-step explanation: