Answers: 2
Mathematics, 20.06.2019 18:04
Here is their argument. given the obtuse angle x, we make a quadrilateral abcd with ∠dab = x, and ∠abc = 90◦, and ad = bc. say the perpendicular bisector to dc meets the perpendicular bisector to ab at p. then pa = pb and pc = pd. so the triangles pad and pbc have equal sides and are congruent. thus ∠pad = ∠pbc. but pab is isosceles, hence ∠pab = ∠pba. subtracting, gives x = ∠pad−∠pab = ∠pbc −∠pba = 90◦. this is a preposterous conclusion – just where is the mistake in the "proof" and why does the argument break down there?
Answers: 2
Mathematics, 21.06.2019 16:00
Which fraction is not equivalent to 8/12 a. 2/3 b. 24/36 c. 4/10 d. 6/10
Answers: 1
Mathematics, 21.06.2019 23:00
Joey is asked to name a quadrilateral that is also a rhombus and has 2 pairs of parallel sides.should be his answer
Answers: 1
How do 2^3 and 2^-3 compare to 10^3 and 10^-3?...
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