Find the solution to the system of equations. x + 4y - 5z = -6
x + 4y - 4z = -1
x + 5y - 4z = 3
A. x = 3, y = 4, z = 5
B. x = 5, y = 3, Z = 6
C. x = 3, y = 13, z = -14
O D. x = 4, y = 5, z = 3

A.

Step-by-step explanation:

first find value of x from eq.1 and 2

then value of y from equation 2 and 3

put these values in equation 1 to get value of x

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15