Answers: 1
Mathematics, 21.06.2019 16:10
To find the extreme values of a function f(x.y) on a curve x-x(t), y y(t), treat f as a function of the single variable t and use the chain rule to find where df/dt is zero. in any other single-variable case, the extreme values of f are then found among the values at the critical points (points where df/dt is zero or fails to exist), and endpoints of the parameter domain. find the absolute maximum and minimum values of the following function on the given curves. use the parametric equations x=2cos t, y 2 sin t functions: curves: i) the semicircle x4,y20 i) the quarter circle x2+y-4, x20, y20 b, g(x,y)=xy
Answers: 2
Mathematics, 21.06.2019 16:50
Which is a true statement comparing the graphs of x^2/6^2-y^2/8^2 = 1 and x^2/8^2-y^2/6^2 the foci of both graphs are the same points. the lengths of both transverse axes are the same. the directrices of = 1 are horizontal while the directrices of = 1 are vertical. the vertices of = 1 are on the y-axis while the vertices of = 1 are on the x-axis.
Answers: 2
Is anyone doing a zoom because I’m bored lol...
Mathematics, 29.06.2020 20:01
Arts, 29.06.2020 20:01
Physics, 29.06.2020 20:01
Biology, 29.06.2020 20:01
Mathematics, 29.06.2020 20:01
Biology, 29.06.2020 20:01