The points (1, 4) and (−3, 2) are the endpoints of a diameter of a circle. What is the equation of the circle?

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Step-by-step explanation:

Since we have the endpoints of the diameter, the midpoint coordinates of the line segment joining them gives the centre of the circle.

That is, centre (a,b) = ( [1+(-3)]/2, [4+2]/2) = (-1,3)

Distance between the given points give the diameter and half of that is the radius length.

So, radius r = (1/2)* sqrt ( [1-(-3)]^2 + [4–2]^2) = sqrt(5)

Thus equation required is: (x-a)^2 + (y-b)^2 = r^2

So, (x+1)^2 + (y-3)^2 = 5

i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

replace   with   27   and simplify.

10 , 27 , 10 , 70 , 10 , 35 , 10 , 48

step-by-step explanation: