Find the x-coordinates of all points on the graph of: f(x)=6sinx-sin^2x
at which the tangent line is horizontal.

The points where the tangent line of f(x) are horizontal are those where f '(x) = 0.

Then find f '(x)

f '(x) = 6cosx - 2sinxcosx = 2cosx (3 - sinx) =0

=> 3 - sinx = 0, which is never

or cosx = 0, which is for x = π/2, 3π/2, 5π2, , -π/2 , -3π/2, -5π/2 , ...

You can represent that by x = π/2 + kπ, for k ∈ Z.
 

0=6x+2y+10 is equivalent to the simplified form: y= -3x - 5• parallel lines always have the same slope, different y intercept knowing this, we can say the slope, or m of the line parallel to y= -3x - 5 is -3.m= -3 hope this could !