At a school cafeteria a cold lunch costs $1.80, and a hot lunch costs $3.00. During one school year a teacher spent a total of $288.60 on cold lunches and hot lunches. The number of cold lunches the teacher bought was 1 fewer than swice the number of hot lunches the teacher bought. Which system of equations can be used to find c, the number of cold lunches, and h, the number of hot lunches, the teacher bought during the school year?

H=44

C=87

Step-by-step explanation:

1.8 (C) + 3.00 (H) = 288.6

C= 2H-1

1.8 (2H-1) + 3 (H) = 288.6

3.6 H -1.8 + 3 H = 288.6

6.6 H = 290.4

H= 290.4/6.6 = 44

C=87

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497