Help plss The rectangle below has an area of 55x^6+22x^455x

6

+22x

4

55, x, start superscript, 6, end superscript, plus, 22, x, start superscript, 4, end superscript.

The width of the rectangle is equal to the greatest common monomial factor of 55x^655x

6

55, x, start superscript, 6, end superscript and 22x^422x

4

22, x, start superscript, 4, end superscript.

What is the length and width of the rectangle?

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

there are infinitely many solutions.