A computer is programmed to generate a sequence of three digits, where each digit is either 0 or 1, and each of these is equally likely to occur. Construct a sample space that shows all possible three-digit sequences of 0s and 1s and then find the probability that a sequence will contain at least one 0. A. 000, 001, 010, 011, 100, 101, 110, 111; P(at least one 0) = Equals StartFraction 7 Over 8 EndFraction b. 000, 001, 010, 100, 101, 110 ; P(at least one 0) = Equals StartFraction 6 Over 6 EndFraction c. 100, 101, 110, 111; P(at least one 0) = Equals three-fourths d. 000, 001, 010, 011; P(at least one 0) = Equals StartFraction 4 Over 8 EndFraction = one-half

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet