engineers want to design seats in commercial aircraft so that they are wide enough to fit 99​% of all males.​ men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 0.9 in. find p99. that​ is, find the hip breadth for men that separates the smallest 99​% from the largest 1​%.

x = 16.45 inches

Step-by-step explanation:

Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. Men have hip breadths that are normally distributed with a mean of 14.4 inches and a standard deviation of 1 inch. find P98. I really don't understand, help needed please.

Find the z-value with a left tail of 0.98

invNorm(0.98) = 2.0537

Find the corresponding x-value using x = zs+u

x = 2.0537*1+14.4

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x = 16.45 inches

set each factor equal to 0

4x-3 = 0

2x-1 = 0

solve for x.

4x-3=0

4x=3

x= 3/4

solve for x. 

2x-1= 0

2x= 1

x= 1/2

your answer should be 1/2 is less than or equal to x and 3/4 is greater than or equal to x