Find the radius of a circle which has a sector area of 9 pi whose central angle is 90 degrees.

360/90 = 4

Total area = 4 times that of the sector.

Step-by-step explanation:

A 90 deg sector has 1/4 the area of the circle.

Total circle area = 4*9pi = 36pi

The area is A= 3/2π

Step-by-step explanation:

The area of whole circle is:

A

c

=

π

×

r

2

=

9

π

The central angle

60

o

is

1

6

of a full angle, so the area of the sector is:

A

s

=

1

6

A

c

=

1

6

×

9

π

=

9

6

π

=

3

2

π

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

c: lkllmn.

hope it's you