A ball is dropped from a height of 64 feet. Its height, in feet, can be modeled by the function h(t) = -16t2 + 64, where t is the time in seconds since the ball was dropped. A. After how many seconds will the ball hit the ground? B. What is a reasonable domain and range for this function?

See solution below

Step-by-step explanation:

The ball will hit the ground at whrn t = 0

Given the height of the ball modeled by the expression

h(t) = -16t^2 + 64

0 =  -16t^2 + 64

16t^2 = 64

t^2 = 64/16

t^2 = 4

t = 2sec

The ball will hit the ground 2secs after

The domain are the values of the input values t and this values start from 2 and greater. Hence the domain of the function is {2, ∞}

when t = 2

h (2) = -16(2)^2 + 64

h(2) = -64+64

h(2) = 0

Hence the range are the output values i.e the height.

The range are within the range {0, ∞}

answer: the two figures are congruent.

step-by-step explanation: they're congruent because figure efgh is reflected across the x and y axis but it was also rotated.

hope it !