Given right triangle ABC with altitude BD drawn to hypotenuse AC. If BC=6 and DC=4, what is the length of AC ?

Step-by-step explanation:

BC^2 + DC^2 = AC^2

6^2 + 4^2 =AC^2

36 + 16 = AC^2

52=AC^2

√52=AC

AC=7.2111

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: