A picture frame has the shape of an ellipse defined by the equation y^2/100+ x^2/ 36= 1 with units in inches. A hook is placed on the back of the picture frame to hang it on the wall. The hook is located at one of the foci of the ellipse. What is the distance from the hook to the top of the picture frame? O 2 in. O 4 in. O 6 in. O 8 in.​

the answer is O 2 in.

Step-by-step explanation:

just find the gcf and solve the gcf's until you get each answer i have a really good feeling somethings missing xd (like the dimensions of the fence) *cough *cough *hint *hint

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204