Help! I really really need this​

A point E is taken on OB such that OC= OE and draw EF perpendicular to OX or OX' .

Since,

< YOB= <XOA

Therefore, < OEF=<COD

Now, from the right- angled traingle EOF and right-angled traingle COD we get ,< OEF= < COD and OE= OX

hence, traingle EOF= Triangle COD ( Congruent)

Therefore, EF=OD, OF= DC, And OE= OC

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it