a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides​

Complete question :

a triangular land having area 36m²and perimeter 84 m has length of the edge 26m. Calculate the measure of remaining two sides​

28cm, 30 cm

Step-by-step explanation:

Area = 336 m³ ; lebgth of edge = 26

Perineter, p = 84

Perimeter of triangle :

a + b + c

Length of other two sides = 84 - 26 = 58

If length of one of the sides = x

Lenvyb if the other = 58 - x

From Hero's formular :

Sqrt(s(s-a)(s-b)(s-c).

s = perimeter /2 = 84/2 = 42

Sqrt(42(42 - 26)(42 - x)(42 - (58-x))

sqrt(42(16)(42-x)(42-58+x) = 336

sqrt(42(16)(42-x)(-16+x) = 336

672(42-x)(x - 16) = 112896

(42 - x)(x - 16) = 168

42x - 672 - x² + 16x = 168

-x² + 58x - 840 = 0

Using the quadratic equation solver, the roots are :

28, 30

Hence.the other tow sides are 28 cm and 30 cm

it's equivalent, so we can say that its equal.

let's call the denominator x and the numerador is 18 less then denominator, x - 18.

multiply

2.x = 5.(x - 18)

2x = 5x - 90

90 = 5x - 2x

90 = 3x

x = 90/3

x = 30

so: