A bag has 4 red marbles, 5 blue marbles, and 6 green marbles. What is the probability if choosing a red marble from the bag, not putting it back, and then choosing a green marble?

4/35

Step-by-step explanation:

Number of red marbles = 4

Number of blue marbles = 5

Number of green marbles = 6

Total number of marbles = 4+5+6 = 15

When a red marble is picked, the probability is 4/15, then to pick a green marble after that, we have 14 marbles left and probability of picking green is 6/14.

Now, probability of choosing a red marble from the bag, not putting it back, and then choosing a green marble will be:

= 4/15 × 6/14

= 24/210

= 4/35

hello from mrbilldoesmath!

answer:   x (x+6)^2, choice b

discussion:

factor x out of the equation:

x^3 + 12x^2 + 36x = x (x^2 + 12x + 36).

note that 6+6 = 12 and 6*6 = 36 so the above factors into:

x (x+6)^2

which is choice b

you,

mrb