PLEASE ANSWER NOW Jane threwl ball into the air. The graph shows the relationship between the number of seconds that the ball was in the air
and the height of the ball.
HEIGHT OF BALL
30
25
20
Height of Ball (in feet)
15
10
5
1
4
5
6
2 3
Time in seconds)
What is the x-intercept for the given function and what does this represent in the situation?
A. 5 seconds; the height where Jane threw the ball
B. 2.5 seconds; the height where Jane threw the ball
C. 5 seconds; the number of seconds it took the ball to hit the ground
OD. 2.5 seconds; the number of seconds it took the ball to hit the ground

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2

fyuh

step-by-step explanation:

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1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.