Does 4x^2-20x+25 equal (2x-5)^2?

Step-by-step explanation:

(2x-5)² = (2x)² - (2x⋅5) - (2x⋅5) + (-5)²

= 4x² - 20x + 25

4x^2-20x+25 DOES equal (2x-5)^2.

Step-by-step explanation:

By factoring 4x^2-20x+25, we have:

4x^2-20x+25 = (2x - 5)(2x - 5) because of the order for this multiplication as FOIL, or first, outside, inside, and last.

Firstly, we take the first numbers 2x * 2x = 4x, so we put this down as

4x^2

We then take the outside numbers 2x * -5 = -10x and also put this down

4x^2 - 10x

We then take the inside numbers 2x * -5 = -10x again and put this down

4x^2 - 10x - 10x, or 4x^2 - 20x

We then take the last numbers -5 * -5 = +25 and put this down

4x^2 - 20 + 25

We now know that 4x^2 - 20 + 25 is equal to (2x - 5)(2x - 5), and

(2x - 5)(2x - 5) is equal to (2x - 5)^2.

3/20

step-by-step explanation:

well, there are 20 outcomes, and 3 of them you want. so, 3/20

step-by-step explanation:

we have

using a graphing tool

see the attached figure

this is a quadratic equation (vertical parabola) open up

the vertex is a > vertex

the domain of the function is all real > interval (-∞,∞)

the range of the function is the > [-6.125,∞)

the function has two x->   and

the function is increasing over the > (0.25,∞)

the function is decreasing over the > (-∞,0.25)