2. A triangle has vertices A(2,5)B(1,- 2) and C(-5,1) De a) The equation of line BC

b) The equation of perpendicular line from A to BC​

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

it would open into a square depending on the type of envelope i’m not sure about the second part

1. perpendicular

2. parallel

3. perpendicular