Which statement about k(x)=-x2-2x+15 is true? A The zeros are -3 and 5, because k(x)= -(x + 3)(x - 5).
B The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).
C The zeros are -5 and -3, because k(x)= -(x + 5)(x + 3).
D The zeros are 3 and 5, because k(x)= -(x - 3)(x - 5).​

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Step-by-step explanation:

The function k(x)=-x2-2x+15 can be re-written as k(x) = -x^2 - 2x + 15, which in turn becomes -(x^2 + 2x - 15) after the negative sign is factored out.

The quantity inside parentheses is equivalent to (x + 5)(x - 3).  Setting this equal to zero, we get (x + 5) = 0 and (x - 3) = 0, so the zeros are {-5, 3}.  

Thus, Answer B is correct:  

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

The zeros are -5 and 3, because k(x)= -(x + 5)(x - 3).

Step-by-step explanation:

The quantity inside parentheses is equivalent to (x + 5)(x - 3).  Setting this equal to zero, we get (x + 5) = 0 and (x - 3) = 0, so the zeros are {-5, 3}.  

11 feet 6 inches and 8 feet 6 inches

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?