What is the equation in vertex form of a parabola with vertex (-2, -2) that opens downward and is stretched by a factor of 5? A) f(x) = −5(x + 2)^2 + 2
B) f(x) = −5(x − 2)^2 + 2
C) f(x) = 5(x + 2)^2 − 2
D) f(x) = −5(x + 2)^2 − 2

C

Step-by-step explanation:

D).  -5(x + 2)^2 - 2.

Step-by-step explanation:

Parabola which Opens down and vertex (-2, -2) is :

f(x) = a(x + 2)^2 - 2 where a is negative

Stretch by factor 5 gives:

-5(x + 2)^2 - 2.

look at the picture.

y-intercept for the function on a picture is 4 → point (0, 4).

y-intercept for the function

is for x = 0. substitute:

y-intercept is 8 → point (0, 8).