The distances and times of practice runs for four students on a cross - country team are shown in the table below. Runner Distance (miles ) 3 Time (minutes 21 Sean 32 Gwen 30 5 Marc Imani 14 2 Select all the statements that are correct . Sean's average time per mile was 7 minutes . Gwen's average time per mile was 8 minutes . Marc's average time per mile was 7 minutes . average time per mile was 6 minutes , Marc had the fastest average time per mile . Sean had the slowest average time per .

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

the answer is 510

step-by-step explanation:

15 • 13 = 195

15 • 12 = 180

15 • 5 = 75

12 • 5 = 60

195 + 180 = 375

375 + 75 = 450

450 + 60 = 510

add a pic of the graph, then ill edit this "answer" and solve it for you : 3

step-by-step explanation:

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west