chord AB is 3cm from the center of the circle, the radius of the circle = 5cm, calculate the length of the chord​

The lenght of the chord is 8 cm.

Step-by-step explanation:

The chord AB is 3 cm from the center of the circle. If we visualize the chord (in a horizontal position) and the radius of the circle (in a diagonal position) we can notice that both of them forms a triangle, with the following dimentions:          

b: is the base =?

s: is one side of the triangle = distance of the chord from the center of the circle = 3 cm

h: is the hipotenuse = radius of the circle = 5 cm

To find the base (or the ohter side of the triangle) we need to use Pitagoras:

The above value is the half of the chord AB, so:

Therefore, the lenght of the chord is 8 cm.

I hope it helps you!    

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hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)