A student performs a test of H0: p = 0.4 versus Ha: p ≠ 0.4 and gets a p-value of 0.03. The student writes: "Because the p-value is not equal to 0.4, we reject the null hypothesis." What is wrong with the student's conclusion? a. The p-value should be compared with a significance level such as α = 0.05, not the hypothesized value of p.

b. The p-value should be compared with the mean, not the hypothesized value of p.

c. The p-value should be compared with the standard deviation, not the hypothesized value of p.

d. The student should have stated the data prove Ha is true.

e. The student should have stated the data prove H0 is true.

Answer is A hope this helps

Step-by-step explanation:

explanation:

infrared radiation has wavelength in the range between 700 nm and 1 mm. lets' convert these values into scientific notation, keeping in mind that:

let's start from the lower value, we have:

(we moved the dot two places to the left, so we increased the exponent by 2 units, from -9 to -7)

the higher value is:

so, the range of wavelength of infrared radiation is:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)