A Ferris wheel is 35 meters in diameter and boarded from a platform that is 3 meters above the ground. The six o'clock position of the Ferris wheel is level with the loading platform. The wheel completes one revolution in 8 minutes. The function, h(t), gives your height in meters above the ground t minutes after the wheel beings to turn. How high are you off the ground after 6 minutes

height = 20.5068 m    

Step-by-step explanation:

Given the data in the question;

First, lets calculate the amplitude, midline and period of 8minutes

Amplitude = 35 / 2 = 17.5

|A| = 17.5

A = - 17.5  { since the wheel starts at 6 o clock }

midline  C = (35/2) + 3

C = 17.5 + 3

C = 20.5

And period is 8 minutes

⇒ 2π/B = 8

8B = 2π

B = 2π/8 = π/4

So our equation will be in the form of;

y = h(t) = Acos(B×t) + C

∴ h(t) = -17.5cos( π/4×t) + 20.5  

Now, How high are you off the ground after 6 minutes

⇒ height = -17.5cos( π/4 × 6) + 20.5

height = -17.5cos( π/4 × 6) + 20.5    

height = -17.5cos( 4.71238898) + 20.5    

height = -17.5 × cos( 4.712) + 20.5  

height = -17.5 × -0.00038898 + 20.5                  

height = 0.0068 + 20.5  

height = 20.5068 m    

the answer is d

step-by-step explanation: