For patients who have been given a diabetes test, blood-glucose readings are approximately normally distributed with mean 127 mg/dl and a standard deviation 10 mg/dl. Suppose that a sample of 4 patients will be selected and the sample mean blood-glucose level will be computed. Enter answers rounded to three decimal places. According to the empirical rule, in 95 percent of samples the SAMPLE MEAN blood-glucose level will be between
the lower-bound of [BLANK] and the upper-bound of [BLANK]

Between the lower-bound of 117 mg/dl and the upper bound of 137 mg/dl.

Step-by-step explanation:

Empirical Rule

The Empirical Rule states that, for a normally distributed random variable:

Approximately 68% of the measures are within 1 standard deviation of the mean.

Approximately 95% of the measures are within 2 standard deviations of the mean.

Approximately 99.7% of the measures are within 3 standard deviations of the mean.

Central Limit Theorem:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean and standard deviation , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean and standard deviation .

In this question:

Mean of 127, standard deviation of 10.

For the sample mean:

By the Central Limit Theorem, mean is 127, while the standard deviation is

According to the empirical rule, in 95 percent of samples the SAMPLE MEAN blood-glucose level will be between?

By the Empirical Rule, within 2 standard deviations of the mean. So

127 - 2*5 = 117 mg/dl

127 + 2*5 = 137 mg/dl.

Between the lower-bound of 117 mg/dl and the upper bound of 137 mg/dl.

mental cunning

explanation:

he is often referred to as a man of twists and turns

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !