The sum of two numbers is 80 The difference is 16 Write and solve a system of equations to find the numbers.

32+48

Step-by-step explanation:

80- 32= 48

80-48= 32

 32; 48

Step-by-step explanation:

Let x be the smaller number, and y be the larger number, then we get

x + y = 80

x - y = 16

x - y = 16

x = 16 + y

x + y = 80

16 + y + y = 80

16 + 2y = 80

2y = 64

y = 32

x - y = 16

x - 32 = 16

x = 48

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18

3 is greater then both of those numbers