[related rates]

each side of a square is increasing at a rate of 6 cm/s. at what rate is the area of the square increasing when the area of the square is 16 cm^2?

Below is the solution: 

A(final)=16cm^2 ds/dT=6 da/dT=? 

A=(s)^2 A=16cm^2 , s=sqrt(A) , s=sqrt(16) , s=4cm 

da/dT=2(s)(6cm/sec) , da/dT=12cm/sec(s) , da/dT=12cm/sec (4cm) 

Answer should be da/dT=48cm^2/sec

Thank you for posting your question here at . I hope the answer will help you. Feel free to ask more questions here.

The correct answer is $90

Answer: v= lwhstep by step explanation: length x width x heightl = 12kmw = 6kmh = 6km12 x 6 = 7272 x 6 = 432therefore your answer would be c) 432 km^3