What is the equation of the line that passes through (-2,-3) and is perpendicular to 2x-3y=6?

The equation given in the question is

2x - 3y = 6
Dividing both sides of the equation by 3, we get
2/3 x - y = 2
y = 2/3 x - 2
Then, from the above equation we can tell that the slope of the line in the graph is 2/3. The slope of a line perpendicular to this slope will be - 3/2. The line also contains the points (-2,-3). 
Then, the equation of the perpendicular line will be
y = mx + b
- 3 = (- 3/2)(- 2) + b
- 3 = 3 + b
b = - 6
Then
y = (-3/2)x - 6
y + 6 = (- 3/2)x
2y + 12 = - 3x
3x + 2y = - 12