Charlie, who is 4 feet tall, walks away from a streetlight that is 16 feet high at a rate of 4 feet per second, as shown in the figure. express the length s of charlie's shadow as a function of time. (hint: first use similar triangles to express s as a function of the distance d from the streetlight to charlie.)

From similarity of triangles we have 
s/4 = (s+d)/16 and so 4s = s + d and therefore s = d/3. Assuming he starts walking at t=0 from the street light (there is no figure to check this out) then d=5t and we then have s = (5/3) t

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20000 as first it increases by 2500 then by 5000 so next it will increase by 10000