Match the range of the function f(x)=x^2+2x-1 to its domain
2
-2
3
-3

See solutions below

Step-by-step explanation:

Match the range of the function f(x)=x^2+2x-1 to its domain

Domains of the function are the input values x i.e 2, -2, 3 and 3

corresponding f(x) for each values are the range

when x = 2

f(2)=2^2+2(2)-1

f(2) = 4 + 4 - 1

f(2) = 7

when x = -2

f(-2)=(-2)^2+2(-2)-1

f(-2) = 4 - 4 - 1

f(-2) = -1

when x = 3

f(3)=3^2+2(3)-1

f(3) = 9 + 6 - 1

f(3) = 14

when x = -3

f(-3)=(-3)^2+2(-3)-1

f(-3) = 9 -6 - 1

f(-3) = 2

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺