How do we find the factors of x2 – 64 Find numbers that multiply to be O but adds to be -64
O Find numbers that multiply to be 1 but adds to be -64
Find numbers that multiply to be -64 but adds to be 1
Find numbers that multiply to be -64 but adds to be 0

The factors of x²-64 is equal to (x-8)(x+8).

Step-by-step explanation:

The given expression is:

x²-64

we know that, 8² = 64

So,

(x²-8²) = (x-8)(x+8) [As (a-b)(a+b) = a²-b²]

So, the factors of x²-64 i equal to (x-8)(x+8).

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.