A bag contains 7 red marbles, 8 blue marbles and green marbles. If two marbles are drawn out of the bag, what is the exact probability that both marbles drawn will be red?

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Step-by-step explanation:

For this problem you will be multiplying 3 probabilities together: P(#1 is blue)*P(#2 is blue)*P(#3 is blue). For the first probability, we just need to divide the number of blue marbles by the total number of marbles which would be 8/18. For the 2nd probability, we need to remember that we have already removed 1 blue marble so that the number of blue marbles remaining is now 7 and the total number of marbles is now 17 to give us 7/17. We would repeat this process to get the third probability and then multiply all the probabilities together.

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)

x = 3 ± √(5+y)