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Mathematics, 08.04.2021 03:30 hey2000
Write the equation of the circle with diameter endpoints of (-6, 3) and (-14, 13).
(x−4)2+(y+5)2=164open paren x minus 4 close paren squared plus open paren y plus 5 close paren squared is equal to 164
(x−10)2+(y+8)2=164open paren x minus 10 close paren squared plus open paren y plus 8 close paren squared is equal to 164
(x−10)2+(y+8)2=41open paren x minus 10 close paren squared plus open paren y plus 8 close paren squared is equal to 41
(x−4)2+(y+5)2=41open paren x minus 4 close paren squared plus open paren y plus 5 close paren squared is equal to 41
(x+10)2+(y−8)2=164open paren x plus 10 close paren squared plus open paren y minus 8 close paren squared is equal to 164
(x+10)2+(y−8)2=41
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Write the equation of the circle with diameter endpoints of (-6, 3) and (-14, 13).
(x−4)2+(y+5)2=16...
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