Find u•v, where 0 is the angle between the vectors u and v.
T
|u|| = 3, ||v|| = 7, 0 = pi/4

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this

hi! i think the answer is 1/2 : )

step-by-step explanation:

tangent z: 4/3

cosine y: 4/5

cotangent y: 4/3