\sqrt{-x+26}=x-6 −x+26=x−6

x = 1 and 10

Step-by-step explanation:

Given the equation \sqrt{-x+26}=x-6, we are to find the value of x

Take the square of both sides

(\sqrt{-x+26})²= (x-6)²

-x+26 = (x-6)²

Expand the parenthesis

-x+26 = x²-12x+36

x²-12x+36+x-26 = 0

x²-11x+10 = 0

x²-10x-x +10 = 0

x(x-10) -1()-10) = 0

(x-1)(x-10) = 0

x - 1 =0 and x - 10 = 0

x = 1 and 10

Hence the value of x is 1 and 10

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