An aeroplane x whose average speed is 500kmlh leaves Lagos airport at 7:00am nd travel 2hours on a bearing of 050%. If then changes its course nd flies on a bearing of 120% to an airstrip. Another aeroplane leaves Lagos airport at 10:00am nd flies on a straight course to d airstrip A. Both planes arrive at the airstrip A at 11:30am. Calculate a. the average speed of y b .the direction of flight y.​

answer: this doesnt make any sense especially the photo.

step-by-step explanation:

i want to die

what the hell man, i just want the points lol

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet