Square abcd was translated using the rule (x, y) → (x – 4, y + 15) to form a'b'c'd'. what are the coordinates of point d in the pre-image if the coordinates of point d’ in the image are (9, –8)?

(13,-23)

Step-by-step explanation:

A sqaure ABCD was translated using the rule (x,y→(x-4,y+15) to form A'B'C'D'. Now the coordinates of point D in the iamge are (9,-8) therefore pre image of point D is

(by using property when a number go form left to right side then sign changes of a number)

( by using property of addition)

similarly, we find value of y

hence, the coordinate of D in pre iamge is (13,-23).

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )