Find the areas of the figures below. Show all work on for each problem.

 A = ≈28.55 cm²

Step-by-step explanation:

It is drawn as if it should be a triangle minus a rectangle with an area of

½(10)(13) - (7)(6) = 23 cm²

However it is not to scale.

The angle on the right side is

θ = arctan10/13 = 37.56859...°

Meaning the right triangle has a height of

h = 4tan37.56859 = 3.07692 cm

So the right triangle has an area of

Ar = ½(3.07692)(4) = 6.15384... cm²

The left hand side consists of a triangle over a rectangle

The height of the triangle is 4, the base is is 4/tan37.56859 = 5.2 cm

so the left area is

(2)(6) + ½(5.2)(4) = 22.4 cm²

So the sum of the areas of the two enclosed shapes is

A = 22.4 + 6.15384... = 28.55384... ≈28.55 cm²

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

step-by-step explanation:

consider an orange peel: if you want to try and lay it flat, you have to stretch it, we know exactly how things are being stretched or squashed at any given point. we have many different map projections because each has different patterns of some projections can even preserve certain features of the earth without